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A 4-year-old Scottish deer dog named Claire has won best in show at the National Dog Show, for the second time in two years. The long-legged black and dark gray dog stuck his nose into the camera and smiled broadly before trotting over to take up his leash with his handler, Angela Lloyd.
Claire knocked out hundreds of other dogs at the annual show hosted by the Kennel Club of Philadelphia. The show took place over the weekend, but the winner was announced during an NBC broadcast on Thanksgiving Day.
This is the first time in 20 years a dog has won twice in a row. Lloyd said Claire was “more confident in herself” this year.
The Scottish Deerhound is one of the tallest dog breeds – a large male can stand 32 inches at the shoulder and weigh more than 100 pounds, according to the American Kennel Club. The breed has a superior hunting ability and is bred to track giant wild red deer. The AKC suggests that you stand at a distance when looking at the Scottish Deerhound to “fully appreciate the majesty of this ancient animal.”
The show’s other finalists included Winter the English Bulldog, the MM Lakeland Terrier, Sasha the Pyrenean Shepherd, Chester the Affenpinscher, Jade the German Shorthaired Pointer and Mo’Ne Kuvasz, a working dog.
There were 196 breeds and varieties of dogs recognized by the AKC at this year’s show. It includes its latest acclaimed breed, a Biewer Terrier, which made its debut at the show and which NBC describes as “an elegant and athletic toy terrier whose sole purpose in life is to love and be loved.” The rumor, a 19-month-old female Biewer Terrier, appeared with a blue glittering bow.
Normally, more than 2,000 dogs compete in the show, but the number was reduced last year by about 70% due to COVID-19 restrictions. Last year’s competition was held without spectators, but fully vaccinated spectators were allowed this year.